2*3y^2=20

Solution for 2*3y^2=20 equation:

2*3y^2=20

We move all terms to the left:

2*3y^2-(20)=0

Wy multiply elements

6y^2-20=0

a = 6; b = 0; c = -20;
Δ = b2-4ac
Δ = 02-4·6·(-20)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{30}}{2*6}=\frac{0-4\sqrt{30}}{12}
=-\frac{4\sqrt{30}}{12}
=-\frac{\sqrt{30}}{3}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{30}}{2*6}=\frac{0+4\sqrt{30}}{12}
=\frac{4\sqrt{30}}{12}
=\frac{\sqrt{30}}{3}
$